On Sep 3, John Edwards said:
>unless ( $status == (1 || 2) ) {
> print "\nport status must be either up or down\n\n";
> exit;
>} else {
> system("/usr/bin/snmpset hostname password
>interfaces.ifTable.ifEntry.ifAdminStatus.$port i $status");
>}
>
>The above says "unless status equals 1 or 2, fail", which is what you need.
Err, not really. It says:
"unless $status equals (1 or 2)"
which is
"unless $status equals 1"
The operators aren't distributive like that. You have to write
unless ($x == 1 or $x == 2) {
instead of
unless ($x == (1 or 2)) {
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
