> -----Original Message-----
> From: Marvin Bonilla [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 24, 2001 1:54 PM
> To: [EMAIL PROTECTED]
> Subject: Problem with scan fields using split
>
>
> Hello
>
> Certainly I have already new in program with perl , so I need
> help with a log scan program, that extract a field
> information from a log file and get some fileds in order to
> use in another program. the log fields looks like this:
>
> Jul 24 11:37:59.878 [13001] (v3.1.2) POP login by user
> "conhosvp" at (m32.ibw.com.ni) 216.226.201.71 Jul 24
> 11:37:59.932 [13002] (v3.1.2) POP login by user "icade" at
> (mdig76.ibw.com.ni) 64.110.119.80
>
> If you see the digits 24 are the second field using split(/
> /,$s) where the white space is the separator, the problems
> begin when the digit is just one, thats mean from 1 to 9, the
> field become third because the split take a white space as
> the second field, that situation results in that i need to
> change the program every time the date change from 1 to 2
> digits to read correctly the fields.
>
> Is there a solutions to avoid this situation with the split
> function?? Thank you for your help.
Use split(' ', $s) or split(/\s+/, $s) instead of split(/ /, $s).
Using / / as your delimiter pattern means to treat each blank as a
delimiter. So "Jul 1" is treated as "Jul", "", "1". The /\s+/ pattern
treats any sequence of one or more whitespace chars as the delimiter (you
could also use / +/ to just use spaces and not other whitespace chars). Per
the documentation, a delimiter of a single space as a string (not a regex)
is the same as delimiting on sequences of whitespace.
perldoc -f split
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