I stand by my reply to this post. Sure, unpack is quicker. But if you use
regex, i always prefer to use my own defined regex's
my $dateis = "2Jul2001";
my ($date,$month,$year) = $dateis =~ /([0-9]+)([A-Za-z]+)([0-9]+)/;
It makes me sleeper at night
----- Original Message -----
From: "John Edwards" <[EMAIL PROTECTED]>
To: "'Will Crain'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, July 03, 2001 3:54 PM
Subject: RE: A Split Question
> Sorry to pick holes in your first post to the list ;) but this part of
your
> suggested regex
>
> (\w{3,})
>
> will match any alphanumeric character (i.e it will match on the numbers or
> letters in the string). By limiting it to three places, you force the
match
> to work. It's not good practice though.
>
> Matching on a non-digit character will produce the same result, with more
> flexibility.
>
> So
>
> ($day, $month, $year) = $date =~ /(\d+)(\D+)(\d+)/;
> ^ ^ ^
> | | |
> Match one or more numbers | |
> | |
> Match one or more NON numbers |
> |
> Match one or more numbers again
>
> HTH
>
> John
>
>
> -----Original Message-----
> From: Will Crain [mailto:[EMAIL PROTECTED]]
> Sent: 03 July 2001 15:41
> To: [EMAIL PROTECTED]
> Subject: RE: A Split Question
>
> -- Original Message --
>
> >My file has dates in it that either come out as "2Jul2001" or
"21Jul2001".
> > So one or two digits for the day, three for the month, and four for the
> >year.
> >
> >So I would like to split out the day, month, year, and am interested in
> >splitting techniques, where there are no delimeters.
> >
>
> This is my first contribution to the list, I hope it helps. You should
> be able to extract your date data using this regex -
>
> ($day, $month, $year) = $date =~ /(\d{1,2})(\w{3,})(\d{4})/;
>
> This assumes $date contains your date string and results in $day, $month
> and $year containing the individual data bits.
>
> Will
>
>
>
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>
>
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