On Wed, 27 Jun 2001, Brett W. McCoy wrote:
> But you can't say $file = "CHR1", beacuse then you are creating a symbolic
> reference to a filehandle. Very bad. Do this instead:
>
> $file = *CHR1;
>
> Then you can properly use your filehandle. What you really want to do is
> create an array of open filehandles (going by the code you had) and then
> do:
>
> print $file[$_] "stuff";
Oops, I'm thinking ahead of myself. You will need to enclose the
filehandle in a block if you use an array:
print { $file[$_] } "stuff";
or you can store the filehandle in a variable:
my $fh = $file[$_];
print $fh "stuff";
-- Brett
http://www.chapelperilous.net/btfwk/
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as he who is ready to die.
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