On Wed, 27 Jun 2001, Paul Johnson wrote:

> > Is that the reason? I would think --'a' would be z, but that is my own
> > internal logic :)
>
> But ++'z' isn't 'a'.

Technically, you can't do ++'z' because you are modifying a constant...
but autoincrementing a variable whose value is 'z' will make it 'aa'.

-- Brett
                                   http://www.chapelperilous.net/btfwk/
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You will win success in whatever calling you adopt.

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