--- Jeff 'japhy' Pinyan <[EMAIL PROTECTED]> wrote:
> On Jun 26, Silvio Luis Leite Santana said:
> >Why does code 1 work, but code 2 doesn't?
> >(the diference is the ; after print)
> >$bissexto and { print "OK\n" };
> >$bissexto and { print "OK\n"; };
>
> In the first code, Perl thinks you're constructing a hash reference.
> In the second code, Perl sees a block where it expects an expression.
Ok, I found the difference -- the semicolon.
I just didn't see it before.
Doh.
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