*? = 0 or more, non-greedy. Non-greeday meaning "as few as possible".
$test = 'foobar foobar'; # matches "foobar foobar", as many of "." as possible. $test =~ /foo.*bar/; # matches "foobar", as few of "." as possible (in this case, none). $test =~ /foo.*?bar/; Also... + = 1 or more (greedy) +? = 1 or more, non-greedy. Rob -----Original Message----- From: Rob Benton [mailto:[EMAIL PROTECTED] Sent: Wednesday, March 19, 2003 2:07 PM To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: Problem with regular expressions!!! How does it translate? * = 0 or more of preceding char ? = 1 or 0 of preceding char *? = ??? On Tue, 2003-03-18 at 21:41, Michael Kelly wrote: > On Tue, Mar 18, 2003 at 05:53:45PM -0600, Rob Benton wrote: > > It looks odd to me b/c * and ? are both quantifiers... > > * and ? alone are both quantifiers, but *? is a non-greedy *. > > -- > Michael > [EMAIL PROTECTED] > http://www.jedimike.net/ > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
