On Wed, 26 Feb 2003 19:47:35 -0500, Casey West wrote: > Here's a nice trick. Use the int() function. It's documented in > perlfunc, a short to the documentation is 'perldoc -f int'. > > When passed a string, int() will return 0. When passed a number, it > will return the integer version of that number. Armed with this > knowledge, it's fair to assume that when passed an integer, the > following expression will be true: > > $data == int( $data );
Sorry, but that's wrong. Have a look to this one liner: perl -e '$x = "123kg"; print "$x is ", ($x == int($x)) ? "numeric" : "a string"' int() interpretes its argument in numeric context what will be with most strings 0 (if the string starts with a non-number). But if it starts with something number-like it's whole a different story. Cheerio, Janek -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
