Thanks Felix. I actually used
$start_discounted_gift_cert = ($total_start) *
($start_discounted_gift_cert_of_total);
$start_discounted_gift_cert = sprintf("%8.2f",$start_discounted_gift_cert);
$giftcert_remainder_first = substr($start_discounted_gift_cert, -5);
$giftcert_remainder_first = sprintf("%8.2f",$giftcert_remainder_first);
substr() works perfectly. Even though substr() works well, i believe that
it was created to be used with strings not numbers. I know that you are all
busy, but can anyone point out anything fundamentally wrong with my
approach?
Thanks,
Andrew
-----Original Message-----
From: Felix Geerinckx [mailto:felix_geerinckx@;hotmail.com]
Sent: Thursday, October 17, 2002 3:06 PM
To: [EMAIL PROTECTED]
Subject: Re: replacing numbers around a decimal
on wo, 16 okt 2002 20:03:31 GMT, Andrew Hughes wrote:
> I am creating a little calculator that is going to need to take a
> user entered number that will always have 2 decimal places (using
> sprintf). It could be 89562321.29 or it could be 101.00) and take
> the last 4 digits (with the period included, so five places) and do
> two things:
>
> 1)Store the number in a variable. For the two examples above that
> would be 21.29 and 01.00 respectively would be stored in their own
> variable x=21.29 or it could be x=01.00; and
>
> 2) replace the last 4 numbers (5 places) with 00.00 -- always. For
> the two examples above they would become 89562300.00 and 100.00. Can
> anyone point me in the right direction?
my $number = 89562321.29;
my $big = int($number/100)*100;
my $small = $number - $big;
printf("%.2f - %05.2f\n", $big, $small);
--
felix
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