> -----Original Message----- > From: Mike Craig [mailto:[EMAIL PROTECTED]] > Sent: Thursday, September 12, 2002 10:02 PM > To: [EMAIL PROTECTED] > Subject: RE: Rounding a number > > > Hi, > > Unless I have missed exactly what you need, this should work > > take the int of Snum + 1
That works unless $num is already an integer. I don't think he wants to round 1.0 to 2 ceil() avoids this problem. > > Mike Craig > > www.UltraTextPro.biz > > > -----Original Message----- > From: Bob Showalter [mailto:[EMAIL PROTECTED]] > Sent: Thursday, September 12, 2002 4:42 PM > To: 'Octavian Rasnita'; [EMAIL PROTECTED] > Subject: RE: Rounding a number > > > > -----Original Message----- > > From: Octavian Rasnita [mailto:[EMAIL PROTECTED]] > > Sent: Thursday, September 12, 2002 4:54 AM > > To: [EMAIL PROTECTED] > > Subject: Rounding a number > > > > > > Hi all, > > > > I would like to round a number but to the next integer not > > like the int > > function does. > > > > I've tried: > > > > my $num = 1.33; > > $num = $num + 0.499999; > > $num = sprintf "%.0f", $num; > > > > This works but I am wondering if there is a cleaner and > > better solution > > because there is a small chance not to work for some numbers. > > It sounds like you want the POSIX ceil() function: > > $ perl -MPOSIX -le 'print POSIX::ceil(1.33)' > 2 > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
