I would have done it like this.
$var = 34.5678;
$var=~/((\d+).(\d{0,2}))/;
$var = $1;
$var=~s/\./,/sg;
printf (" The formated value is : $var");
---OUTPUT----
The formated value is : 34.56
Well there may be better and more straigth forward ways, I was just trying
to get used to Patterns and subsititution.
with regards
Rajeev Rumale
----- Original Message -----
From: "Wagner Garcia Campagner" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, October 01, 2001 9:18 PM
Subject: formating variables again...
> Hi,
>
> I have a variable $var = 34.5678
>
> If I
>
> printf ("%.2f", $var);
>
> Then $var = 34.56
>
> Is there a way for me to format $var to became 34,56 instead of 34.56 ???
>
> Thanks,
> Wagner.
>
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>
>
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