Tillema, Glenn <[EMAIL PROTECTED]> said something to this effect on 07/17/2001:
> I know there must be an easy way to do this but the solution evades me
> and I'm hoping someone here either knows the answer or can point me in
> the right direction so I can figure it out myself ... on to the
> question;
>
> I have two scalars, each contain a comma-seperated list of values;
>
> $scaOne = "1,2,3,4,5";
> $scaTwo = "label one,labelTwo,label,label4,label five";
>
> I want to put these into a hash where the end result would be this;
>
> %hashOne = ( 1 => 'label one',
> 2 => 'labelTwo',
> 3 => 'label',
> 4 => 'label4',
> 5 => 'label five',);
The easy way to do this is to split $scaOne and $scaTwo and use
them in a hash slice:
$scaOne = "1,2,3,4,5";
$scaTwo = "label one,labelTwo,label,label4,label five";
@one = split /,/, $scaOne;
@two = split /,/, $scaTwo;
@h{@one} = @two;
Or, more succicntly, replace the last three lines with:
@h{split ',', $scaOne} = (split /,/, $scaTwo);
This requires that $scaOne and $scaTwo have the same number of
fields in them (but your problem suggests that they will).
(darren)
--
The question of whether computers can think is just like the question of
whether submarines can swim.
-- Edsger W. Dijkstra
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