Try using pdb. Check the values of next and prev when it is called for the second time. Similarly check the values of next and prev in another execution. You will enjoy it :-).
Try going through this answer: http://stackoverflow.com/questions/1132941/least-astonishment-in-python-the-mutable-default-argument. Thanks Shankha Banerjee On Sat, Oct 4, 2014 at 4:57 PM, Rajiv Subramanian M <rajiv.m1...@gmail.com> wrote: > Hi Group, > > I just went through this article > http://docs.python-guide.org/en/latest/writing/gotchas/ > > written a Fibonacci program like this > > def fibonacci(next=[1], prev=[0]): > data = prev.pop() > prev.append(next.pop()) > next.append(prev[0] + data) > return data > > for i in range(10): > print fibonacci() > > It actually works, it prints first 10 fibonacci numbers > > My question is the following code doesn't work the same way as i expected > it to work. > > def fibonacci(next=1, prev=0): > data = prev > prev = next > next = data + next > return data > > for i in range(10): > print fibonacci() > > Instead of printing Fibonacci, it just prints 10 zeros > > means.. does python only remembers the list in default argument? > > -- > > [image: --] > Rajiv Subramanian M > [image: http://]about.me/rajiv.m1991 > <http://about.me/rajiv.m1991?promo=email_sig> > _______________________________________________ > BangPypers mailing list > BangPypers@python.org > https://mail.python.org/mailman/listinfo/bangpypers _______________________________________________ BangPypers mailing list BangPypers@python.org https://mail.python.org/mailman/listinfo/bangpypers
