Another way:
from collections import defaultdict
x = [['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog', 'NM56', 65]]
y = [['cat', 'NM123, NM234', 12], ['dog', 'NM56', 65]]
def f(acc, x):
acc[(x[0], x[2])] += [x[1]]
return acc
assert y == [[k[0], ', '.join(v), k[1]] for k, v in reduce(f, x,
defaultdict(list)).iteritems()]
On Thu, Dec 5, 2013 at 3:00 PM, Nitin Kumar <nitin.n...@gmail.com> wrote:
> long but this too works :)
>
> >>> p=[]
> >>> x=[['cat','NM123',12],['cat','NM234',12], ['dog', 'NM56',65]]
> >>> import copy
> >>> def fn(a,b):
> if len(a)==3 and a[0]==b[0] and a[-1]==b[-1] and a[1]!=b[1]:
> a.insert(-1,b[1])
> p.append(a)
> else:
> p.append(b)
> return p
>
> >>> reduce(fn, copy.deepcopy(x))
> [['cat', 'NM123', 'NM234', 12], ['dog', 'NM56', 65]]
> >>> p
> [['cat', 'NM123', 'NM234', 12], ['dog', 'NM56', 65]]
> >>>
> >>>
> >>> x
> [['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog', 'NM56', 65]]
> >>> 'p is your y'
>
> Nitin K
>
>
> On Thu, Dec 5, 2013 at 1:55 PM, Vikram K <vikthirtyf...@gmail.com> wrote:
>
> > Any suggestions on what i have to do to go from x to y?
> >
> > >>> x = [['cat','NM123',12],['cat','NM234',12], ['dog', 'NM56',65]]
> > >>> x
> > [['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog', 'NM56', 65]]
> > >>> y = []
> > >>> y = [['cat','NM123, NM234', 12], ['dog', 'NM56', 65]]
> > >>>
> >
> > Regards
> > Vik
> > _______________________________________________
> > BangPypers mailing list
> > BangPypers@python.org
> > https://mail.python.org/mailman/listinfo/bangpypers
> >
> _______________________________________________
> BangPypers mailing list
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>
--
Vineet Naik
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