On 11/25/2010 04:10 PM, Kenneth Gonsalves wrote:
On Thu, 2010-11-25 at 15:56 +0530, Anand Balachandran Pillai wrote:
> r'(^0\d{2}[-\s]{1}[1-6]{1}\d{7})|(^0\d{3}[-\s]{1}[1-6]{1}\d{6})|(^0
> \d{4}[-\s]{1}[1-6]{1}\d{5})'
>
It is doable, but you should really use pyparsing for this - this is
UGLY !
I know - but everything I tried to make it look good did not work. And
the app in which I am plugging this into requires an re.
Certainly, you can beautify that using the verbose option. Here is my attempt.
(Note, I use the beautiful (?(id/name)yes-pattern|no-pattern) syntax for the
black magic :)
phone_re = re.compile(r"""
(^0 # all std-codes start with 0
(
(?P<twodigit>\d{2}) | # the std-code group
(?P<threedigit>\d{3}) | # either two, three or four digits
(?P<fourdigit>\d{4}) # following the 0
)
[-\s] # space or -
[1-6] # first digit of phone number
(
(?(twodigit)\d{7}) | # 7 more phone digits for 3 digit stdcode
(?(threedigit)\d{6}) | # 6 more phone digits for 4 digit stdcode
(?(fourdigit)\d{5}) # 5 more phone digits for 5 digit stdcode
)
)$""", re.VERBOSE)
hth,
cheers,
- steve
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