Hi Nitin,
On 07/29/2010 02:18 PM, Nitin Kumar wrote:
Hi all,
Say I have 10 functions in base class and I have inherited it in some
derived class.
But I only want 9 of the base class function to be available in child class.
(and I don’t want to make that one class private)
Python encourages clear design by not providing facilities to /enforce/ policies
as part of the language. That's the reason why there are no
public/protected/private keywords in python. There are only conventions to be
followed. Here are some possible solutions:
a. Are you sure you got your class hierarchy right ? If one class needs all the
methods of the other except one, the one with the most commonality should
probably be the base class. In your case, it would be flipping the hierarchy on
it' head.
b. If some method is 'special' to a class name it using leading and trailing
'__' so that users deriving from the class know it is special.
c. This is now going into hacky territory -- if you decide to keep the same
hierarchy as you have now, assign self.A in class 'y' to None[1] or explicitly
implement it to raise an AttributeError[2]. The reason you cannot 'del' self.A
is precisely because of what the error says "AttributeError: y instance has no
attribute 'A'" -- A is just a 'bound' method to the object, not an attribute of
the object and AFAICT there is no way to un-bind something off an object.
[1]
class y(x):
def __init__(self):
super(y, self).__init__() # btw, use super if possible
self.A = None
[2]
class y(x):
def __init__(self):
...
def A(self):
raise AttributeError("y instance has no attribute A")
hth,
cheers,
- steve
--
random spiel: http://lonetwin.net/
what i'm stumbling into: http://lonetwin.stumbleupon.com/
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