On Tuesday 27 July 2010 12:18 PM, Vikram wrote:
have the following:
x
[['NM100', 1, 2], ['NM100', 3, 4], ['NM200', 5, 6]]
for i in x:
... print i
...
['NM100', 1, 2]
['NM100', 3, 4]
['NM200', 5, 6]
------
how does one obtain list z such that
z = [['NM100',1,2,3,4],['NM200',5,6]]
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A less readable solution using itertools
#------------
from itertools import *
get_first = lambda x: x[0]
filter_first_and_chain_rest = lambda seq: chain(*(x[1:] for x in seq))
data = [['NM100', 1, 2], ['NM100', 3, 4], ['NM200', 5, 6]]
grouped = groupby(sorted(data), get_first)
print list ([label] + list(filter_first_and_chain_rest(grp)) for label,
grp in grouped)
~Shekhar
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