On Thu, Jul 22, 2010 at 7:00 PM, steve <st...@lonetwin.net> wrote:
> Hi,
>
>
> On 07/22/2010 05:02 PM, Anand Balachandran Pillai wrote:
>
>> On Thu, Jul 22, 2010 at 3:21 PM, Vikram<kp...@rediffmail.com> wrote:
>>
>> Suppose you have the following list:
>>>
>>> >>> x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>>
>>> My problem is that i wish to obtain the following two dictionaries:
>>> xdictstart = {'cat':10, 'dog':1}
>>> xdictend = {'cat':30, 'dog':5}
>>>
>>
>>
>> Any nice way to do the above? Thanks.
>>>
>>>
>>> Yes. Try this.
>>
>> x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>>>> x.sort()
>>>>> xdictstart = dict(reversed(x))
>>>>> xdictend = dict(x)
>>>>> xdictstart,xdictend
>>>>>
>>>> ({'dog': 1, 'cat': 10}, {'dog': 5, 'cat': 30})
>>
>
> Are you sure that'll work ? Is creating a dict from a sequence guaranteed
> to be executed serially withing the sequence ?
It is nowhere mentioned in Docs IIRC but I have never seen any counter
example.
>
>
> cheers,
> - steve
> --
> random spiel: http://lonetwin.net/
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--
~l0nwlf
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