On Fri, May 28, 2010 at 12:49 PM, murugadoss <murugadoss2...@gmail.com> wrote:
> Hello all,
>
> I am trying a sample program for send set of data [ kept in array]. I have
> attached the code below,
>
> import struct
>
> sendvalues = [181, 98, 11, 01]
> for i in range(4):
> snddata = struct.pack('int',int(sendvalue[i]))
> sendto(sndData,("localhost"))
'int' is not a valid struct.pack format specifier. You'll have to say
'i'. Since you have 4 arguments (all signed integers), you'll have to
say 'i'*4.
Something like
struct.pack('i'*4, *sendvalues)
will pack all four integers into a string. The * before sendvalues it
to unpack the list into arguments. You can send it then. If you want
to send it int by int, you can put
snddata = struct.pack('i', sendvalue[i])
in your loop (the int constructor is redundant since all the elements
are integers anyway).
Also, you wouldn't use "for i in range(4)" to loop through a list in
Python. You'd say
for i in sendvalues:
snddata = struct.pack('i', i)
...
> i am getting error as,
>
> Traceback (most recent call last):
> File "./clientudp.py", line 10, in <module>
> snddata = struct.pack('hhl',sendvalue[i])
> File "/usr/local/lib/python2.5/struct.py", line 63, in pack
> return o.pack(*args)
> struct.error: pack requires exactly 3 arguments
This is somewhat fundamental. Are you sure you read
http://docs.python.org/library/struct.html before trying this? If not,
you know what to do. :)
--
~noufal
http://nibrahim.net.in
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