Hi, Many thanks to all.. I tried cell_overwrite=True and its working fine..!!
On Wed, Feb 10, 2010 at 6:13 PM, Kent Johnson <ken...@tds.net> wrote: > On Wed, Feb 10, 2010 at 6:47 AM, nikunj badjatya > <nikunjbadja...@gmail.com> wrote: > > > I commented out the "raise Exception" statement in Row.py library > > module. > > Here's the (line no. 150 ) of Row.py which i have edited: > > > > def insert_cell(self, col_index, cell_obj): > > if col_index in self.__cells: > > if not self.__parent._cell_overwrite_ok: > > msg = "Attempt to overwrite cell: sheetname=%r rowx=%d > > colx=%d" \ > > % (self.__parent.name, self.__idx, col_index) > > #raise Exception(msg) > > #########*commented to avoid error. > > prev_cell_obj = self.__cells[col_index] > > sst_idx = getattr(prev_cell_obj, 'sst_idx', None) > > if sst_idx is not None: > > self.__parent_wb.del_str(sst_idx) > > self.__cells[col_index] = cell_obj > > > > The excel sheet creation code now works fine. > > > > My question is, Instead of manually goin to /usr/lib/.../row.py and > > commenting out the line, Can this be done through few lines of code in > > my program itself. ?? > > Looking at the code above, you can see that the exception is raised > only if self.__parent._cell_overwrite_ok is False. So there is an > option to allow overwriting. > > From the error message it appears that self.__parent is a Worksheet. > Looking at the source code for Worksheet.py, the __init__() method > does have an optional cell_overwrite_ok= parameter. This parameter is > also available in Workbook.add_sheet(). So if you pass > cell_overwrite=True to add_sheet() you should be OK. > > Kent > _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
