On Thu, Jul 16, 2009 at 1:10 PM, Madhubala<madhuba...@infotechsw.com> wrote:
> Posted earlier with wrong description in the subject - sorry.
> Hi,
>
> I would like to put one design for discussion and would like to get
> appropriate solution after discussions. The details are below.
>
> There are three dictionaries like
> goodObjects {name:object} # object can be any data type which cannot/need
> not hold its type as good etc. badObjects {name:object}
> unknownObjects {name:object}
>
> The requirement here is to display all these objects sorted by name and show
> different colors for good/bad/unknown
This is what I would do:
l = [(name, object, 'good') for name, object in goodObjects.iteritems()]
l.extend(((name, object, 'bad') for name, object in badObjects.iteritems()))
l.extend(((name, object, 'unknown') for name, object in
unknownObjects.iteritems()))
Now "sorted(l)" will give you the list you want.
But I agree with the earlier poster who implied that you should
consider re-organizing your data structures so you don't find yourself
in this situation.
navin.
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