The syntax looks familiar, almost python like.
The equivalent python code would be*:
def poll_reg(bit_pos, poll_val, reg_offset):
matched = 0
while matched != 1:
read_data = read_reg(reg_offset)
if read_data[bit_pos] === poll_val:
matched = 1
else:
matched = 0
return matched
* Implementing read_reg is left as an exercise to the developer :p
I'm not aware of any python library methods which allow one to access
registers. But, the read_reg() can be implmented in C and
imported into Python.
Any low level operation like register access is usually delegated to .
HTH,
PG
On Sep 19, 2008, at 7:02 PM, Deepak Patel wrote:
Hello all,
I want to a write a method in Python to poll a register for '1' or
'0'. It is kind of very simple in verilog, but not sure if python
provides flexibility or not.
My algorithm (kind of Verilog syntax where I can access the bits
without any extra processing) is as follows:
poll_reg ( input bit_pos, input poll_val, reg_offset)
{
// In this bit_pos is the position of bit in my register read which
are being polled to become poll_val. Poll_val can be either 0 or 1.
matched = 0;
while (matched != 1)
begin
read_data = read_reg(reg_offset);
if (read_data[bit_pos] == poll_val)
begin
matched = 1;
end
else
begin
matched = 0;
end
end
}
Is there a way to do above in Python?
Thanks,
Deepak
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