On 25.06.13 15:28, Klaus Rudolph wrote:
> if I set pc to the first jump address (0x1a)
>
> set $pc=0x1a
> the output is as follows:
> 0x0080001a: std Y+50, r10 ; 0x32
> 0x0080001c: muls r21, r31
> 0x0080001e: std Y+50, r10 ; 0x32
> 0x00800020: nop
>
> Why I got an address in ram space?
Hopefully I'm not missing something¹, but the only "address" I can see
is the displacement of 0x32 (decimal 50). You'll have to place a
breakpoint, and read the register to see where the std would end up.
(Sorry, it's so long since I used simulavr, that I don't remember all
that it can do, but that much must be there.)
Have you been away from avr for a spell, Klaus? ;-)
Erik
¹ It's nearly midnight here, so that's quite possible.
--
Wizards had always known that the act of observation changed the thing that
was observed, and sometimes forgot that it also changed the observer too.
Terry Pratchett - Interesting times
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