Stu Bell <sb...@dataplay.com> wrote: > You are trying to set a global through the initializer to a variable > value. At *compile time*, what is the value of TIME[0]? Unknown.
No, __TIME__[0] /is/ known at compile-time, because __TIME__ gets replaced by a string literal by the preprocessing stage. Pass the given code through a C++ compiler, and it will work quite fine. The point here is that a string literal in C is essentially an initialized array variable. While the user is not allowed to ever modify that variable (so the compiler could put it into an umodifiable location, and the compiler is allowed to share the storage for identical string literals), syntactically it remains a variable anyway. C does not have a real notion of a constant, despite the "const" keyword introduced in ISO C90. As such, the right-hand side of the above initializer, albeit in effect constant and known at compile-time, does not form "constant expression" per the syntax rules of the C language. C++ is different in that it has real constants, and as such a string literal there /is/ a constant, so accessing an element of that literal in the right-hand side of the initializer of an object with static storage is allowed. -- cheers, J"org .-.-. --... ...-- -.. . DL8DTL http://www.sax.de/~joerg/ NIC: JW11-RIPE Never trust an operating system you don't have sources for. ;-) _______________________________________________ AVR-GCC-list mailing list AVR-GCC-list@nongnu.org http://lists.nongnu.org/mailman/listinfo/avr-gcc-list
