"Eric Weddington" wrote:
> ...
> I agree with the statement above that "'volatile' is precisely to warn the
> compiler that it should not 'reason' anything about [the] variable".
> However, David brings up a good point. A local variable is put on the stack,
> generally not the place for hardware to modify the variable. And generally,
> other parts of the program (such as ISRs) don't have access to the specific
> location of the variable on the stack. Both hardware and ISRs work with
> global variables. So *could* a compiler reason that local variables could
> never be volatile? Or are there truly situations where hardware or ISRs
> could modify local variables on the stack?
Yes, ISRs and hardware can modify variables on the stack.
uint8_t *g1;
ISR1()
{
*g1 = 1;
}
main()
{
volatile uint8_t v = 0;
g1 = &v;
// configure ISRs and enable interrupts
...
}
-Preston
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