I may be wrong but I'm going to venture a guess here that you can't write a binary literal in C. I tried a simple example with the syntax mentioned here on standard GCC (non-AVR) and got the same error mentioned. I also looked around the net and found nothing about how to do so.
It seems I remember seeing in one language or another that you COULD represent binary literals but I've tinkered in so many who knows which it was. Probably Ada. Is there some reason you can't specify your constant as hex? Hex is always a safe bet and is almost always represented the same way in all languages. I believe the original poster said he was new to programming. If so, just remember that each hex digit represents four binary bits/digits with decimal values of 0-15. It won't take long at all to get where reading hex, both for decimal value and bit pattern, happens without thinking about it. HTH, Tubbs --- Vincent Trouilliez <[EMAIL PROTECTED]> wrote: > > GCC 3.4.3 must work for > > > > foo = 0b11110000; > > OR > > foo = 0B11110000; > > > > Are you getting compilation errors? > > > > Nayani > > > Hi Nayani, > > Yes, I get a compiler error in both cases. > > About foo = 0b1111000; or foo = 0B11110000; it says > : > > main.c:92:9: invalid suffix "b11110000" on integer > constant > > ...and about foo = b11110000; it says: > > main.c:92: error: `b11110000' undeclared (first use > in this function) > > > > Regards, > > > -- > Vince > > > > _______________________________________________ > AVR-GCC-list mailing list > AVR-GCC-list@nongnu.org > http://lists.nongnu.org/mailman/listinfo/avr-gcc-list > _______________________________________________ AVR-GCC-list mailing list AVR-GCC-list@nongnu.org http://lists.nongnu.org/mailman/listinfo/avr-gcc-list
