I've an application that has a directory structure like this. ./src ./src/non_gui ./src/gui
In the non_gui directory there are about 6 binaries, which will build easily one any system. In the gui directory, there is currently one (probably more later) binaries that require all sorts of libraries to be installed. I want the configure script to accept configure --with-gui before it will build the bits in gui. How is the *best* way to go about this. I have failed miserably. The main problem seems to be that src/Makefile.am either has to have # This is src/Makefile.am, which is proceed by automake SUBDIRS = non_gui gui EXTRA_DIST = README tests in which case a makefile src/gui/Makefile is expected to be made. I've configured the configure.in so the makefile does not get made by ending it with if test "x$with_gui" = "xyes"; then AC_OUTPUT([ Makefile src/Makefile src/gui/Makefile src/ non_gui/Makeile]) else AC_OUTPUT([ Makefile src/Makefile src/ non_gui/Makeile]) Rather than ask how to tweak my method so it does work, can anyone tell me the best way to implement a system so that make will only try to build files in one particular directory if a certain option is given to configure. -- Dr. David Kirkby PhD, email: [EMAIL PROTECTED] web page: http://www.david-kirkby.co.uk Amateur radio callsign: G8WRB
