This init is useless because base.sched will be cleared to 0 in
drm_sched_job_init
because of 2320c9e6a768 ("drm/sched: memset() 'job' in drm_sched_job_init()").
Signed-off-by: Pierre-Eric Pelloux-Prayer <pierre-eric.pelloux-pra...@amd.com>
---
drivers/gpu/drm/amd/amdgpu/amdgpu_job.c | 5 -----
1 file changed, 5 deletions(-)
diff --git a/drivers/gpu/drm/amd/amdgpu/amdgpu_job.c
b/drivers/gpu/drm/amd/amdgpu/amdgpu_job.c
index e9e2e107ed45..72973568cd1f 100644
--- a/drivers/gpu/drm/amd/amdgpu/amdgpu_job.c
+++ b/drivers/gpu/drm/amd/amdgpu/amdgpu_job.c
@@ -198,11 +198,6 @@ int amdgpu_job_alloc(struct amdgpu_device *adev, struct
amdgpu_vm *vm,
if (!*job)
return -ENOMEM;
- /*
- * Initialize the scheduler to at least some ring so that we always
- * have a pointer to adev.
- */
- (*job)->base.sched = &adev->rings[0]->sched;
(*job)->vm = vm;
amdgpu_sync_create(&(*job)->explicit_sync);
--
2.43.0
