http://stackoverflow.com/questions/3127454/how-do-c-class-members-get-initialized-if-i-dont-do-it-explicitly

On Sun, Sep 28, 2014 at 12:22 PM, Deepak Garg <[email protected]>
wrote:

> Hi
>
> In example 1, member z will have a garbage value (i.e. 0 in your case )
>
> Thanks
> Deepak
> On Sep 28, 2014 11:29 AM, "sagar sindwani" <[email protected]>
> wrote:
>
>> I am working on How compilers handle initialization list. I came across a
>> case where I am not sure what should be the compiler behaviour.
>>
>> *Example 1:-*
>>
>> #include <iostream>
>>
>> class A
>> {
>>     public:
>>         int x,y,z;
>> };
>>
>> int main()
>> {
>>     A a1[2] =
>>     {
>>         { 1,2 },
>>         { 3,4 }
>>     };
>>
>>     std::cout << "a1[0].z is " << a1[0].z << std::endl;
>>
>>     return 0;
>> }
>>
>> In above case a1[0].z is ? g++ shows it as 0 ( zero ). It is exactly 0 or
>> garbage value, I am not sure on that.
>>
>> I tried lot of books and some documents , no where I found what C++ says
>> for initialization of class objects.
>>
>> You can find handling of below case in almost every book.
>>
>> *Example 2:- *
>>
>> int arr[6] = {0};
>>
>> In Example 2,  compilers will auto-fill all members with 0. It is
>> mentioned in books. But when it comes to User-defined datatypes nothing is
>> mentioned.
>>
>>
>> Please share your thoughts on this. If you find any document related to
>> this, please share it as well.
>>
>> Thanks
>> Sagar
>>
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