Here is a fairly simple way to find a solution.

Make a list of each pair of the n cards which have been selected. This list 
can include up to 300 pairs. Represent each card as a 10-bit value where 
each bit represents one particular color or value. Thus, each card will 
have two bits set. Each pair is the bitwise XOR (^) of the values of the 
card, indicating which hints will distinguish those two cards. Now try all 
1024 possible combinations of hints by iterating i from 0 to 1023. If the 
bitwise AND (&) of i with any value in the pair list is zero, that 
combination of hints would not distinguish those cards. So a valid 
combination of hints has a non-zero bitwise AND with all values in the 
pairs list. Find the value of i with the fewest bits which meets this 
condition.

Don

On Tuesday, July 1, 2014 12:15:14 PM UTC-4, vikas wrote:
>
> One of my friend posted this question to me and I am unable to get 
> anywhere. Could you guys please help 
>
> A game of cards has 5 colors and 5 values. Thus a total of 25 cards are 
> possible. Player 1 will choose n cards and tell you exactly , what all 
> cards he has. Then he will spread cards in front of you with face downwards 
> in random fashion.
> So you know the card values but not the ordering. Player 1 will provide 
> you 2 types of hints , he can tell you what all cards have some color or he 
> can tell you what all cards have some value. you need to tell the ordering 
> of cards with the help of these hints.
> challenge is to find out minimum number of hints to be provided by player 
> 1 so that you are able to make it for all cards.
>
> e.g. say player chosen n=5 cards
> and tells you the values
>
> B1 Y1 W1 G1 R1
>
> he can either tell you that what all cards are 1 (in this case all cards)
> or can tell you different color like leftmost is color 'B" and next after 
> 'Y' and so on. So minimun hints in this case is 4
>
>  
> another example
> if n=4
> G4 R3 R4 B3
>
> Here he can tell you the card 1st and 3rd are of  values 4 and cards 2 and 
> 3 are of color 'R'. This will be sufficient to infer the card values. so 
> answer is 2
>
>
> I am not interested in code , please suggest plain simple algorithms, if 
> possible with arguments that why it is correct ?
>
>

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