Yes i agree that my recurrence relation is wrong. I have checked it some
inputs, it did not work. But i think the brute force solution is possible
in O(n^3) solution. We have O(n^2) combination of end points. we can check
for the maximum possible even length palin string in O(n). So that will
give O(n^3). Anyone has solution about O(n^2)?


On 5 June 2014 22:25, Saurabh Paliwal <[email protected]> wrote:

> Hi all!
> Well, I agree with Shashwat in that Kumar is wrong with his solution. For
> example a string " kumarxyzramuk " will tell you why.
> I have a solution which runs in O(n*n) time. It is top-down dynamic
> programming approach. Let me know if you don't understand something or if
> there is some glitch in the solution. I think it is correct.
>
> Link to the C++ code  - http://ideone.com/Qzs990
>
>
> On Thu, Jun 5, 2014 at 7:13 PM, Shashwat Anand <[email protected]> wrote:
>
>> Code ?
>>
>>
>> On Thu, Jun 5, 2014 at 7:08 PM, kumar raja <[email protected]>
>> wrote:
>>
>>> U have two dimensions for the table ( has O(n^2) entries.) and to check
>>> whether string is palindrome or not it will take O(n) . So it is O(n^3)
>>> solution.
>>>
>>> I have checked it manually for some inputs, and it works.
>>>
>>>
>>> On 5 June 2014 18:53, Shashwat Anand <[email protected]> wrote:
>>>
>>>> I am not too sure about your O (N^3) solution even.  Can you link the
>>>> working code ?
>>>>
>>>>
>>>> On Thu, Jun 5, 2014 at 6:48 PM, kumar raja <[email protected]>
>>>> wrote:
>>>>
>>>>> This is a very good collection of DP problems.
>>>>>
>>>>> I want the answers for problem 2(e)
>>>>> and problem 14.
>>>>>
>>>>> for problem 14 the recurrence relation
>>>>> that i have is
>>>>>
>>>>> T[i,j] = 0 if i>=j
>>>>>            1 if j=i+1 and s[i]=s[j]
>>>>>            0 if j=i+1 and s[i]!=s[j]
>>>>>            j-i+1/2 if s[i..j] is even length palindrome
>>>>>            j-i/2      if s[i..j] is odd length palindrome
>>>>>            max{T[i+1,j],T[i,j-1]} else
>>>>>
>>>>> But this is O(n^3) solution. Could not
>>>>> find out solution of order O(n^2).
>>>>> If someone knows please share the answers for them.
>>>>>
>>>>>
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>
>
>
> --
>  -    Saurabh Paliwal
>
>        B-Tech. Comp. Science and Engg.
>
>        IIT ROORKEE
>
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