@dave you are correct but language of question implies---> out of 8 coins 3 taken together weigh x,again 3 coins taken out of 8 have y as weight . This shows that one or more coins out of 3 (weight x) may be same as those considered for weight y as so on for z and w.
On Sat, Mar 2, 2013 at 2:39 AM, Dave <[email protected]> wrote: > @Maddy: I'm a little confused because there are 8 coins in the bag but 3 + > 3 + 2 + 2 = 10 coins are grouped by weight. > > Dave > > On Friday, March 1, 2013 1:15:03 PM UTC-6, maddy wrote: > >> >> There are 8 coins in a bag . >> 3 coin weights x kg >> 3 coins weights y kg >> 2 coins weights z kg >> 2 coins weights w kg >> You have to separate them into separate heaps according to >> their weights in minimum comparisons using weighing balance. >> >> >> -- >> Regards, >> SHUBHAM SANDEEP >> IT 3rd yr. >> NIT ALD. >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/groups/opt_out. > > > -- Regards, SHUBHAM SANDEEP IT 3rd yr. NIT ALD. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
