So far what atul mentioned is I think the best and the most intuitive
approach. O(nlog(n)).

On Fri, Feb 22, 2013 at 11:22 PM, Karthikeyan V.B <[email protected]>wrote:

> @Aditya :
>
> Since k<m and we need the element that apears exactly k times, i think u
> need to find the smallest number in the array and the corresponding index
> is the number that is repeated most number of times.
>
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