by match u mean that number of fruits that overlap with i th fruit but are
not sliced before time i.
which means we have to consider 2^m cases where m is the maximum number of
fruits that overlap with ith fruit.
And this we have to do for each fruit.

On Mon, Jan 28, 2013 at 12:54 AM, Nikhil Karnwal <[email protected]>wrote:

> Actually dp[i] represent the state in which u make a slice at appearing
> time of i th fruits.and match represent the overlapping fruits
> with i.
> so
> for each i dp[i]=max(dp[i],dp[j]+match);
> for all j=[0,i] and match =overlapped fruits with i which are not sliced
> until the cut of j.
> Hope this will help.
> Thanks
>
> On Thu, Jan 24, 2013 at 10:18 PM, foram lakhani <[email protected]>wrote:
>
>> Thanx for the reply but I didnt get you. What does dp[i] represent ?
>>
>>
>> On Thu, Jan 24, 2013 at 9:50 PM, sunny <[email protected]> wrote:
>>
>>> take a structure or pair of start time and finish time and then sort the
>>> the structure you know the comparator function  the for each for each dp[i]
>>> select j belongs to  (0,i) and then count the overlap value
>>>
>>>
>>>                                 if(j==0)
>>> dp[i]=max(dp[i],match);
>>> else
>>>  dp[i]=max(dp[i],dp[j-1]+match);
>>>
>>>
>>> with this recursive relation my code got accepted in .24 sec others
>>> approach you mentioned may lead to the TLE
>>>
>>> On Thursday, January 24, 2013 1:35:38 PM UTC+5:30, emmy wrote:
>>>>
>>>> please help me with the following problem:
>>>>  http://www.spoj.com/problems/**JUICE/<http://www.spoj.com/problems/JUICE/>
>>>>
>>>> bit mask will require very large memory.
>>>> If I sort the intervals in decreasing order of their start time.. I
>>>> still cant make it to a dp
>>>> If I sort the intervals in decreasing order of their finish times I am
>>>> still not getting a recurrence for dp that is valid
>>>> If I convert this to an interval graph, I have to find the maximum
>>>> number of vertices that can be included in some clique of size >=3. But
>>>> this also seems like a brute force approach.
>>>>
>>>> Which approach to try?? please help!!
>>>>
>>>>  --
>>>
>>>
>>>
>>
>>  --
>>
>>
>>
>
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