you see, in each step of recursion, the number of digits in *n* is decrease
by one(at least in worst case), so the complexity you can decide.
On Tuesday, November 13, 2012 3:34:06 PM UTC+5:30, Shruti wrote:
>
> hi
>
> Can anyone help me find out the time complexity of recursive gcd algorithm
> (using euclid's algo)
> i.e. for the following program :
>
> int gcd(int n,int m) //given n>m
> {
> if(n%m==0)
> return m;
> else
> return gcd(m,n%m);
>
> }
>
> i think the soln is lg(a*b) but have no idea how..
>
>
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