@ vishal :let array be {5,2,1,1} ==> as per u'r algo =>{1,2},{1,5} are sets
difference is 3 .. but the sol is {5}{1,1,2} ==> diff = 1;

On Fri, Nov 16, 2012 at 10:12 AM, vishal chaudhary <[email protected]
> wrote:

> Hi
> Sorry for that as i misinterpreted the question.
> for the difference to be minimum, i think(not completely sure) we can
> first sort the array
> and then we can start putting the elements at even index in the last part
> of the array and the odd ones in the starting in the new array
> you can do this in the same array itself i guess but you have to do some
> kind of shifting.
> by doing this for all the elements and dividing them into two groups.
> I hope this helps.
>
> Vishal
>
>
>
> On Fri, Nov 16, 2012 at 9:46 AM, bharat b <[email protected]>wrote:
>
>> @ vishal : how can u divide an array into 2 groups whose difference is
>> maximum in O(1). why max?
>>
>> solution : http://www.youtube.com/watch?v=GdnpQY2j064
>>
>>
>>
>>
>> On Fri, Nov 16, 2012 at 9:22 AM, vishal chaudhary <
>> [email protected]> wrote:
>>
>>> Hi
>>> you can first sort the array which can be done in O(nlogn) complexity if
>>> the number of items in the array is n.
>>> Then using the indexing of arrays you can divide the array into two
>>> groups whose difference is going to be maximum and this can be done in O(1)
>>> complexity.
>>> So the complete algorithm is going to take O(nlogn) complexity.
>>> Kindly share an alternative algorithm if you find  one with lower
>>> complexity.
>>>
>>> Vishal
>>>
>>>
>>> On Wed, Nov 7, 2012 at 7:43 PM, Arun Kindra <[email protected]
>>> > wrote:
>>>
>>>> Given an unsorted array, how to divide them into two equal arrays whose
>>>> difference of sum is minimum.
>>>>
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