..i under stand with 6!/(3!*3!) method...
plz explain from combination point of view....i didnt get ur last line....i
understand that

we need to find no. of permutaions of abcxyz s.t a<b<c and x<y<z.....plz
tell how to find this....i understand as someone explained above with
VVVHHH method.....
please explain from thsi view that

we need to find no. of permutaions of abcxyz s.t a<b<c and x<y<z.


On Sat, Oct 27, 2012 at 12:31 PM, Saurabh Kumar <[email protected]>wrote:

> Since this is a small grid you can count it manually but in general
> problem is to count no. of paths from bottom-left corner to top-right
> corner (provided all the transition alphabets in the automata are distinct
> in the respective dimensions e.g. here,  xyz in one  dimension and abc in
> other)
>
> You can view this problem as writing all permutations of strings of 3R's
> and 3U's (for RIGHT movement and UP movement) RRRUUU which will take you to
> the top right most corner.
> All possible arrangements = (3+3)! / (3! * 3!)
> In general: (m+n)! / (m! * n!) for a mxn grid.
>
>
> On 27 October 2012 11:05, rahul sharma <[email protected]> wrote:
>
>> should i take it how many ways are there to reach from start to  the top
>> right destination...x,y,z,a,b,c, are i/p state....xyzabc one string....abc
>> xyz is another...if m ryt then is dere any formulla to calute or we have to
>> do it manuallyyyy
>>
>>
>> On Sat, Oct 27, 2012 at 11:02 AM, rahul sharma 
>> <[email protected]>wrote:
>>
>>>
>>> can u please elaborate...i am not able to understand the figure..plz
>>> explain....it would be of great help
>>>
>>> On Sat, Oct 27, 2012 at 5:57 AM, payal gupta <[email protected]>wrote:
>>>
>>>> should be 6C3 or 20 perhaps.
>>>>
>>>> On Sat, Oct 27, 2012 at 3:29 AM, rahul sharma 
>>>> <[email protected]>wrote:
>>>>
>>>>> Finite state automata accpt string of length 6
>>>>>
>>>>> what is total number of strings in set..please find the attahcment
>>>>>
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