i - j is giving -3 as output. why is this so ?
On Tue, Oct 16, 2012 at 11:18 PM, iwill <[email protected]> wrote:
> how to explain the output if instead of j-i we try to print i-j ?
>
>
> On Saturday, October 13, 2012 3:36:49 PM UTC+5:30, bharat wrote:
>>
>> #include<stdio.h>
>> main()
>> {
>> int *i,*j;
>> i=(int*)60;
>> j=(int*)71;
>> printf("%d",j-i);
>> }
>>
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