because of null char in 1st
On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma <[email protected]>wrote:
> char str[]="ab";
> char str1[]={'a','b'};
>
> sizeof(str) ...o/p is 3
> sizeof(str1)....o/p is 2..
>
> Why so????
> plz explain...--
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