Your approach sounds like the optimal (and linear) algorithm for the
submass finding problem. But if I recall correctly that only works in
linear time if the input is entirely positive integers?
Maybe I'm being stupid but wont checking that array be quadratic?

On 2 September 2012 20:02, Navin Kumar <[email protected]> wrote:

> @pradip: Finding same element in temp array is little bit tricky. For
> displaying item from i+1 to j , you have to make sure that there is equal
> element at i and j index in temp array. How will you ensure it in O(n) time?
>
>
> On Sun, Sep 2, 2012 at 3:16 PM, Pradeep Mishra 
> <[email protected]>wrote:
>
>>  This algorithm is *O(n)*.
>>
>> Given an int[] input array, you can create an int[] tmp array where tmp[i]
>> = tmp[i - 1] + input[i]; Each element of tmp will store the sum of the
>> input up to that element.
>>
>> Now if you check tmp, you'll notice that there might be values that are
>> equal to each other. Let's say that this values are at indexes j an k
>> with j < k, then the sum of the input till j is equal to the sum tillk and
>> this means that the sum of the portion of the array between j and k is
>> 0! Specifically the 0 sum subarray will be from index j + 1 to k.
>>
>>    - NOTE: if j + 1 == k, then k is 0 and that's it! ;)
>>    - NOTE: The algorithm should consider a virtual tmp[-1] = 0;
>>
>> Correct me if i am wrong Thanx
>>
>> --
>> Pradeep Kumar Mishra
>> IIIT Allahabad
>> B. Tech 3rd Year ( IT )
>> Another Mail - [email protected]
>>
>>
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