@Rahul kumar Dubey
#include<stdio.h>
double fn(char *a , int b , char c)
{
return (1.1);
}
int main()
{
int it = 2;
char ct = 'c';
char a[30];
printf("%d\n",(sizeof(fn)));
}
why it is always giving output as 1 irrespective of the return type of
function ??
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