^sorting a string would be o(n^2logn) if u use q.sort.count sort would be better. Saurabh Singh B.Tech (Computer Science) MNNIT blog:geekinessthecoolway.blogspot.com
On Wed, Jul 18, 2012 at 1:08 PM, vindhya chhabra <[email protected]>wrote: > sort the list,sort the word(use quick sort(nlogn time))- and den search > using binary search(logn time) > or we can evn do by hashing-hash the word,den for every word keep > decreasing the counter,if the hash array is zero ,anagram,else reset the > hash array for given input for the checking the next word. > > > On Wed, Jul 18, 2012 at 2:07 AM, Navin Kumar <[email protected]>wrote: > >> Assuming a preexisting list of 100 words, how would you efficiently see >> if a word received from input is an anagram of any of the 100 words? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To view this discussion on the web visit >> https://groups.google.com/d/msg/algogeeks/-/5kuxjymYEc4J. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Vindhya Chhabra > > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
