http://stackoverflow.com/questions/1900197/generating-variations-without-repetitions-permutations-in-java/


On Wed, Jul 4, 2012 at 8:16 PM, Nishant Pandey <[email protected]
> wrote:

> the code works fine only in case of duplicates , but if we consider
> string to be non duplicates like say :"abc" then all permutation cant be
> obtainned .
>
>
> On Wed, Jul 4, 2012 at 12:31 PM, atul anand <[email protected]>wrote:
>
>> you can use flag[256];
>>
>> now you just need to check
>> loop:
>>     if (flag[str[i]]==0)
>>     {
>>      //swap()
>>      //permute function call
>>      //swap()
>>      flag[str[i]=1;
>>     }
>> done
>>
>>
>> On 7/4/12, atul anand <[email protected]> wrote:
>> > you can use flag[256];
>> >
>> > now you just need to check
>> > loop:
>> >     flag[str[i]]==0)
>> >     {
>> >      //swap()
>> >      //permute function call
>> >      //swap()
>> >      flag[str[i]=1;
>> >     }
>> > done
>> >
>> > On 7/3/12, Nishant Pandey <[email protected]> wrote:
>> >> 1) Find all permutations of a string.
>> >> 2) Improve it so that the permutations are not repeated, Eg=> string is
>> >> "aaaa"
>> >> Answer should be just aaaa once not 4! times.
>> >>
>> >> i want suggestion to improve the recursive code in case of 2) case .
>> >>
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>> >>
>> >
>>
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-- 
Abhishek Sharma
Under-Graduate Student,
PEC University of Technology

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