@sengar: sorry dude...i got his doubt.Though my explanation was correct. I
think now everybody's doubt is clear.By the way thanx for correcting me.

On Fri, Jun 8, 2012 at 11:48 AM, sengar.mahi <[email protected]> wrote:

> @naveen :read the his doubt properly...he was expecting 5 10 15 but was
> getting 8 32 96...and dats the correction required which i made
>
>
> On Fri, Jun 8, 2012 at 8:08 AM, Navin Kumar <[email protected]>wrote:
>
>> @Mahendra: for ur above code with t=(a<<2)+a o/p will be 5,10, 15 as i
>> explained above. without bracket answer will be 8 , 32 and 96 because +
>> precedence is higher than <<.
>>
>>
>> On Fri, Jun 8, 2012 at 7:31 AM, Mahendra Sengar <[email protected]>wrote:
>>
>>> Cracked it...i guess precedence of + is more than <<
>>> so
>>> use t=(a<<2)+a;
>>>
>>> I checked, its giving proper output now !!!
>>>
>>>
>>> On Friday, June 8, 2012 5:46:09 AM UTC+5:30, algo lover wrote:
>>>>
>>>> The following is a simple C program which tries to multiply an integer
>>>> by 5 using the bitwise operations. But it doesn't do so. Explain the reason
>>>> for the wrong behavior of the program.
>>>>
>>>>   #include <stdio.h>
>>>>   #define PrintInt(expr) printf("%s : %d\n",#expr,(expr))
>>>>   *int* FiveTimes(*int* a)
>>>>   {
>>>>       *int* t;
>>>>
>>>>
>>>>
>>>>       t *=* a*<<*2 *+* a;
>>>>
>>>>
>>>>
>>>>       *return* t;
>>>>   }
>>>>
>>>>   *int* main()
>>>>   {
>>>>       *int* a *=* 1, b *=* 2,c *=* 3;
>>>>
>>>>
>>>>
>>>>       PrintInt(FiveTimes(a));
>>>>       PrintInt(FiveTimes(b));
>>>>
>>>>
>>>>
>>>>       PrintInt(FiveTimes(c));
>>>>       *return* 0;
>>>>   }
>>>>
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