@Rahul: but for heapify, i need to build heap tree first from the list.
which will cost linear traversal of the elements, that will cost O(n). but
i need to search it in O(log n) or polylogrithmic complexity of (log n)
i.e. (log^2 n).

On Sun, Jun 3, 2012 at 8:55 AM, Rahul Kumar Patle <[email protected]
> wrote:

> @abhinav: if you want to search just 15 in log(n) time then you can use
> the concept of heap tree.. apply one round of heapification (not for all
> elements but just one time it will be complete in log(n) times), and you
> will need to swap elements but when you got element 15 you can stop..
> although space complexity has increased... you will need one redundant
> array to use heap operation so that finally you will have original array as
> it is...
>
> Thanks and Regards:
> Rahul Kumar Patle
>
>
> On Sun, Jun 3, 2012 at 8:31 PM, abhinav gupta <[email protected]>wrote:
>
>>
>>   We have given a list 14 6 7 15 8 9 ............we have to find 15 in
>> (log n ) times.
>> --
>>
>> *Thanks and Regards,*
>>
>> Abhinav Kumar Gupta
>> **[email protected]
>>
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-- 
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
*Technical Skill is the mastery of complexity, while Creativity is the master
of presence of mind. **  *









                      - Morihei Ueshiba
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
*Thanks and Regards,*

Abhinav Kumar Gupta
*M. Tech. (Software Engineering)*
Motilal Nehru National Institute of Technology
Allahabad(UP)-211004
+919628358065
[email protected]

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