@Ramakant : i guess you shud include diagonal case also ....
for each arr[i][j]
if(arr[i][j]==1)
{
if (!(arr[i-1][j]==1 || arr[i][j-1]==1 || arr[i-1][j-1]))
count++;
}
On Tue, Jan 10, 2012 at 9:33 AM, Ramakant Sharma <[email protected]>wrote:
> Scan the matrix row wise left to right........
> for each arr[i][j]
> if(arr[i][j]==1)
> {
> if (!(arr[i-1][j]==1||arr[i][j-1]==1))
> count++;
> }
> ///also chk for baundary values accordingly
>
>
>
>
> 1 1 0 0
> 1 1 0 0
> 0 0 1 1
>
>
> i think it should work..
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to [email protected].
> To unsubscribe from this group, send email to
> [email protected].
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
