@Ankur : i guess this would work but to your test add one more sizeof(arr);

On Wed, Jan 4, 2012 at 10:00 PM, Ankur Garg <[email protected]> wrote:

> sorry it shud be
> sum of squares and xor and sumof elements
>
> I think this shud work
>
> Regards
> Ankur
>
>
>
>
> On Wed, Jan 4, 2012 at 9:52 PM, atul anand <[email protected]>wrote:
>
>> @ Karthikeyan :
>>
>> sum of cubes fails:-
>>
>> arr1={2,3,0,-3} =   4
>> arr2={1,1,1,1}  = 4
>>
>> On Wed, Jan 4, 2012 at 6:53 PM, Karthikeyan V.B <[email protected]>wrote:
>>
>>> Hi,
>>>
>>> Consider, arr1={1,2,3}  and arr2={-1,-2,-3}
>>>
>>> using sum of squares method sum(arr1) = 14 ans sum(arr2) = 14 (since
>>> square of 1 and -1 is 1)
>>>
>>> so it won work with this case
>>>
>>> 1.better take the square and negate it before adding
>>> or
>>> 2.take sum of cubes
>>>
>>> pls correct me if i'm wrong
>>>
>>> Regards,
>>> Karthikeyan
>>> PSG TECH
>>>
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