Can you please elaborate...

On Thu, Nov 24, 2011 at 12:14 AM, atul anand <[email protected]>wrote:

>
> yes levenshtein distance and BK tree can be used to solve this.
> where edge weight between nodes is equal to levenshtein distance.
>
>
> On Wed, Nov 23, 2011 at 7:14 PM, abhishek kumar <[email protected]>wrote:
>
>> You are given a word and a dictionary. Now propose an algorithm edit
>> the word (insert / delete characters) minimally to get a word that
>> also exists in the dictionary. Cost of insertion and deletion is same.
>> Write pseudocode for it.
>>
>> Seems like minimum edit distance problem but some modification is
>> needed.
>>
>>
>> --
>> Abhishek Kumar
>> B.Tech(IT) Graduate
>> Allahabad
>> Contact no-+919663082731
>>
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