logic:

N=3.. k=5th(position).....length...

no. of setbit :0...

000  k =5

no. of setbit :1.. on every loop get next number of same number of bits and
decrement k by 1.....
001    k = 4
010    k=3
100    k= 2

no. of setbit: 2
011     k=1..
101
110

Therefore answer is 011

complexity : O(n)...


With regards,

Praveen Raj
DCE-IT
9999735993
[email protected]

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