thanx Balaji....:)
On Thu, Sep 22, 2011 at 6:07 AM, Balaji <[email protected]>wrote:
> Hi Anil,
>
> #a is a preprocessor operator to convert the argument specified as string
> or enclosing in double quotes. so, after macro expansion, the printf
> statement would become
>
> printf("%d\n",*"432"); =>
>
> printf("%d\n","432"[0]);=>
>
> printf("%d\n",*"4");
>
> which prints the ASCII equivalent 52.
>
>
> Similarly, using printf("%d\n", "432"[1]),printf("%d\n", "432"[2]) would
> yield 52 and 51 respectively. Let me know.
>
>
> Thanks,
>
> Balaji
>
>
>
> On Wed, Sep 21, 2011 at 4:34 PM, Anil Arya <[email protected]> wrote:
>
>>
>>
>>
>> #include<stdio.h>
>>
>> #define power(a) #a
>>
>> int main(){printf("%d\n",*power(432));return 0;}
>>
>> why it is giving 52 as output?
>>
>>
>>
>>
>>
>> --
>> *Anil Arya,
>> Computer Science *
>> *Motilal Nehru National Institute of Technology,Allahabad .
>> *
>>
>>
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--
*Anil Arya,
Computer Science *
*Motilal Nehru National Institute of Technology,Allahabad .
*
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